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In an examination 85% students pass in English and 65% pass in Mathematics. If 60 % students pass both these subjects, then what percentage of student failed in both subjects

  • A.40 %
  • B.35 %
  • C.15 %
  • D.10 %

Answer: D

10 % of the students failed in both subjects.

Find the percentage who passed in at least one subject, using the rule for the union of two sets:

\[ \begin{aligned} P(E \cup M) &= 85 + 65 - 60 = 90\% \\ \text{failed both} &= 100 - 90 = 10\% \end{aligned} \]

15% is the share who failed English (100 − 85) and 35% the share who failed Mathematics (100 − 65); neither is the share who failed both. 40% is the share who did not pass both subjects (100 − 60), a larger group that includes those who passed one of them.

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