Discussion
Once the design point is chosen, the wing area follows from
Answer: C
Correct answer: Dividing the design weight by the chosen wing loading
Wing loading is weight per unit wing area, so the area follows by rearrangement:
\[ S = \frac{W}{(W/S)} \]
A design weight of \( 640 \) kN at a wing loading of \( 5.8 \) kN/m\(^2\) therefore needs about \( 110 \) m\(^2\). Multiplying instead of dividing gives a nonsensical figure some thirty times too large. The installed thrust follows in the same way from the other coordinate, \( T = W \times (T/W) \), and these two numbers are the principal output of the whole analysis.
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