Discussion
An aircraft of mass \( 52000 \) kg has a wing area of \( 105 \) m\(^2\). Its wing loading is
Answer: C
Correct answer: 4.86 kN/m\(^2\)
Convert the mass to weight before dividing by the area:
\[ W = 52000 \times 9.81 = 510.1\ \mathrm{kN} \]
\[ \frac{W}{S} = \frac{510.1}{105} = 4.86\ \mathrm{kN/m}^2 \]
The distractor \( 495 \) divides the mass in kilograms by the area without converting to weight, giving kg/m\(^2\) - a perfectly valid unit but not the one asked for. Mixing the two conventions is the commonest error in this calculation; the factor between them is \( g \).
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