Discussion
An aircraft's design point sits at \( W/S = 5.5 \) kN/m\(^2\) and \( T/W = 0.30 \). If the weight estimate rises by \( 8 \) per cent with the design point held, the wing area and thrust both rise by
Answer: A
Correct answer: 8 per cent
Both quantities are obtained by multiplying or dividing the design weight by a fixed ratio:
\[ S = \frac{W}{(W/S)}, \qquad T = W \times \frac{T}{W} \]
With the design point held, both ratios are unchanged, so both \( S \) and \( T \) scale in direct proportion to \( W \) - an 8 per cent weight growth gives 8 per cent more wing and 8 per cent more thrust. This linearity is what drives the weight growth spiral: a heavier aircraft needs a bigger wing and bigger engines, which are themselves heavier, and the loop must be iterated to convergence.
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