Discussion
Stalling and approach speeds against wing loading at a landing lift coefficient of 2.6.
| \( W/S \) (kN/m\(^2\)) | Stall speed (m/s) | Approach at 1.23 \( V_s \) (m/s) |
|---|---|---|
| 4.0 | 50.1 | 61.6 |
| 5.0 | 56.0 | 68.9 |
| 6.0 | 61.4 | 75.5 |
| 7.0 | 66.3 | 81.5 |
If the approach speed must not exceed 70 m/s, the maximum wing loading is closest to
Answer: B
Correct answer: 5.0 kN/m\(^2\)
Read down the approach speed column against the \( 70 \) m/s limit. At \( 5.0 \) kN/m\(^2\) the approach speed is \( 68.9 \) m/s, just within it; at \( 6.0 \) it is \( 75.5 \) m/s, well outside. The maximum permissible wing loading therefore lies between the two and is closest to \( 5.0 \).
That value is exactly what the vertical landing constraint would be drawn at. Note how quickly the margin disappears: a 20 per cent increase in wing loading costs almost 10 per cent in approach speed, because the speed varies as the square root of the loading.
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development