Discussion
In the mode word format of 8251 during initialization, \(D_{6}\) and \(D_{7}\) bits as 0 and 1 signify
Answer: D
The bits D6 = 0 and D7 = 1 in the mode word of the 8251 signify 1.5 stop bits, option (D). In the mode instruction of the 8251 USART, bits D7 and D6 select the number of stop bits: 01 means 1 stop bit, 10 means 1.5 stop bits, 11 means 2 stop bits, and 00 is invalid. With D7 = 1 and D6 = 0, the code is 10, which is 1.5. The baud rate factor, option (A), is set by bits D1 and D0. The character length, option (B), is set by D3 and D2. The parity enable and the even parity, option (C), are set by D4 and D5. So only (D) is fixed by D6 and D7.
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