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There is a non-abelian group of order :

  • A.49
  • B.41
  • C.15
  • D.12

Answer: D

There is a non-abelian group of order 12.

The alternating group \(A_{4}\) and the dihedral group \(D_{6}\) of the hexagon both have order 12 and are non-abelian.

The other orders force commutativity. 41 is prime, so the group is cyclic. 49 = \(7^{2}\), and every group of order \(p^{2}\) is abelian. 15 = 3 x 5 with 3 not dividing \(5 - 1\), so the only group of order 15 is cyclic.

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