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How many combinations are possible while selecting four letters from the word ‘SMOKEJACK’ with the condition that ‘J’ must appear in it?

  • A.81
  • B.8/2
  • C.3/2
  • D.41

Answer: D

SMOKEJACK has nine letters with K appearing twice. J must be one of the four, so three more are chosen from S, M, O, K, E, A, C - with K available twice.

At most one K - choose 3 of the 7 distinct letters:

\[ {}^{7}C_{3} = 35 \]

Both K's - choose 1 more from the other 6:

\[ {}^{6}C_{1} = 6 \]

\[ 35 + 6 = 41 \]

The repeated K is what makes this more than a plain \( {}^{7}C_{3} \); the two-K selections are genuinely different combinations.

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