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A boy has nine trousers and 12 shirts. In how many different ways can he select a trouser and a shirt?

  • A.21
  • B.12
  • C.9
  • D.108

Answer: D

The two choices are independent, so they multiply.

\[ 9 \times 12 = 108 \]

Each of the nine trousers can be paired with each of the twelve shirts. Adding them would answer a different question - how many garments he could pick one of.

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