Discussion
A committee has 5 men and 6 women. What are the number of ways of selecting 2 men and 3 women from the given committee?
Answer: B
The two selections are independent, so their counts multiply.
\[ {}^{5}C_{2} \times {}^{6}C_{3} = 10 \times 20 = 200 \]
Order does not matter within either group, so combinations are used rather than permutations.
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