Discussion
A group consists of 4 men, 6 women and 5 children. In how many ways can 2 men , 3 women and 1 child selected from the given group?
Answer: B
The three selections are independent, so their counts multiply.
\[ {}^{4}C_{2} \times {}^{6}C_{3} \times {}^{5}C_{1} \]
\[ = 6 \times 20 \times 5 = 600 \]
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