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Hydrogen atom is excited from ground state to another state with principal quantum number equal to 4. Then the number of spectral lines in the emission spectra will be

  • A.2
  • B.6
  • C.5
  • D.3

Answer: B

Six spectral lines appear.

An electron falling from level \(n\) can reach any lower level, so the number of possible transitions is \[\frac{n(n-1)}{2} = \frac{4\times 3}{2} = 6\] The six are 4→3, 4→2, 4→1, 3→2, 3→1 and 2→1.

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