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An aeroplane is flying horizontally with a velocity of 600 km/h and at a height of 1960 m. When it is vertically at a point A on the ground a bomb is released from it. The bomb strikes the ground at point B. The distance AB is

  • A.1200 m
  • B.0.33 km
  • C.3.33 km
  • D.33 km

Answer: C

The bomb strikes the ground 3.33 km from A.

Vertically it starts with no downward velocity: \[t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2\times1960}{9.8}} = 20\ \mathrm{s}\]

Horizontally it keeps the aircraft's speed of \(166.7\ \mathrm{m\,s^{-1}}\): \[x = 166.7\times20 \approx 3.33\ \mathrm{km}\]

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