Discussion
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in .. ?
Answer: C
Let the slower pipe take \( x \) minutes; the faster one is three times as quick and so takes \( x/3 \). Their rates add:
\[ \frac{1}{x} + \frac{3}{x} = \frac{4}{x} = \frac{1}{36} \quad\Longrightarrow\quad x = 144 \text{ minutes} \]
Seen another way, the two pipes contribute in the ratio 1 : 3, so the slower one does a quarter of the work and needs four times the joint time: \( 4 \times 36 = 144 \). The faster pipe alone would take 48 minutes.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development