Discussion
A tap can fill a tank in 6 hours. After half the tank is filled, three more similar taps are opened. What is the total time taken to fill the tank completely?
Answer: B
Time taken by one tap to fill half of the tank = 3 hrs.
| Part filled by the four taps in 1 hour = | ![]() |
4 x | 1 | ![]() |
= | 2 | . |
| 6 | 3 |
| Remaining part = | ![]() |
1 - | 1 | ![]() |
= | 1 | . |
| 2 | 2 |
![]() |
2 | : | 1 | :: 1 : x |
| 3 | 2 |
x = |
![]() |
1 | x 1 x | 3 | ![]() |
= | 3 | hours i.e., 45 mins. |
| 2 | 2 | 4 |
So, total time taken = 3 hrs. 45 mins.
No comment is present. Be the first to comment.
Loading…
Post your comment
Please log in or register to post a comment.
Examination Categories
- SSC Exams
- Banking Exams
- Teaching Exams
- Civil Services Exams
- Railways Exams
- Engineering Recruitment Exams
- Defence Exams
- State Government Exams
- Police Exams
- Insurance Exams
- Nursing Exams
- Other Government Exams
- NRA CET
- PG Entrance Exams
- Campus Placement
- MBA Entrance Exams
- CUET and UG Entrance
- Judiciary Exams
- Regulatory Body Exams
- Software Development



x =