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Pipes A and B can fill a tank in 20 hours and 30 hours, respectively. Pipe C is an emptying pipe. When all the three pipes are opened together, \(\frac{2}{9}\)th part of the tank is filled in 8 hours. Pipe C alone can empty \(\frac{1}{3}\)rd part of the tank in:

  • A.4 hours
  • B.3 hours
  • C.5 hours
  • D.6 hours

Answer: D

Pipe C alone empties one-third of the tank in 6 hours. A and B together fill \(\frac{1}{20} + \frac{1}{30} = \frac{1}{12}\) of the tank per hour. With C also open, \(\frac{2}{9}\) of the tank fills in 8 hours, so the net rate is \[ \frac{2/9}{8} = \frac{1}{36} \] C's emptying rate is \[ \begin{aligned} \frac{1}{12} - \frac{1}{36} &= \frac{2}{36} \\ &= \frac{1}{18} \end{aligned} \] so C empties the whole tank in 18 hours and one-third of it in \(\frac{18}{3} = 6\) hours. The answer 18 hours would be for the whole tank; 3, 4 and 5 hours do not follow from the rate.

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