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Suppose that \(X_{1}\) and \(X_{2}\) are independent random variables having Bernoulli distribution with mean \(p\) and \(2p\) respectively, where \(0 \lt p \lt 1/2\). The following are two statements :

(I) \((X_{1}, X_{2})\) is minimal sufficient for \(p\)
(II) \(2X_{1} + 5X_{2}\) is minimal sufficient for \(p\)

Which of the following is true ?

  • A.Only (I) is true
  • B.Only (II) is true
  • C.Both (I) and (II) are true
  • D.Neither (I) nor (II) is true

Answer: C

Both (I) and (II) are true.

The joint pmf is \(p^{x_{1}}(1 - p)^{1 - x_{1}}(2p)^{x_{2}}(1 - 2p)^{1 - x_{2}}\). The four sample points give likelihoods \((1 - p)(1 - 2p)\), \(p(1 - 2p)\), \(2p(1 - p)\) and \(2p^{2}\). No two of these have a ratio free of \(p\); for instance \(p(1 - 2p)/[2p(1 - p)] = (1 - 2p)/(2(1 - p))\) depends on \(p\). So no two points can be merged, and the full sample \((X_{1}, X_{2})\) is minimal sufficient.

The statistic \(2X_{1} + 5X_{2}\) takes the values 0, 2, 5 and 7 on the four points, one value per point, so it is a one-to-one function of \((X_{1}, X_{2})\) and is minimal sufficient too.

The trap is to assume a minimal sufficient statistic must reduce the data. Here the sum \(X_{1} + X_{2}\) is not even sufficient, because it merges (1, 0) and (0, 1), whose likelihoods have different shapes. So the options denying (I) or (II) are wrong.

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