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Which of the following probability laws is not a member of an exponential family ?

  • A.\(f(x, \theta) = \theta(1 - x)^{\theta - 1}\), \(0 \lt x \lt 1\), \(\theta \gt 0\)
  • B.\(f(x, \theta) = \theta^{x}(1 - \theta)^{1 - x}\), \(x = 0, 1\), \(0 \lt \theta \lt 1\)
  • C.\(N(\theta, \theta^{2})\), \(\theta \in \mathbf{R}\)
  • D.\(N(\theta, \theta)\), \(\theta \gt 0\)

Answer: C

The law that is not a member of the (one-parameter) exponential family is N(θ, θ2).

Writing the density,

\[ \begin{aligned} f(x) &\propto \frac{1}{\theta}\exp(Q), \\ Q &= -\frac{x^{2}}{2\theta^{2}} + \frac{x}{\theta} - \frac{1}{2} \end{aligned} \]

the exponent has two terms, \(x^{2}\) and x, with coefficients \(-1/(2\theta^{2})\) and \(1/\theta\) depending on the single parameter. It cannot be written as \(c(\theta)T(x)\) with one statistic, so it is a curved family, not a one-parameter exponential family.

The others are members: \(\theta(1 - x)^{\theta - 1} = \exp[(\theta - 1)\log(1 - x) + \log\theta]\); the Bernoulli is \(\exp[x\log\frac{\theta}{1 - \theta} + \log(1 - \theta)]\); and for \(N(\theta, \theta)\) the x term reduces to the constant 1, leaving only \(-x^{2}/(2\theta)\).

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