Discussion
What will be the output of the following C code?
#include <stdio.h>
int main()
{
int i = 11;
int *p = &i;
foo(&p);
printf("%d ", *p);
}
void foo(int *const *p)
{
int j = 10;
*p = &j;
printf("%d ", **p);
}
Answer: A
Correct answer: Compile time error
Read the declaration int *const *p from the inside out: p is a pointer to a const pointer to int. So *p is const-qualified.
The statement *p = &j attempts to assign to that const-qualified object, which the compiler rejects. Compare int **const p, where the const applies to p itself and *p remains modifiable - the position of the qualifier relative to the asterisks decides which level is protected.
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