Discussion
What will be the output of the program assuming that the array begins at location 1002?
#include <stdio.h>
int main()
{
int a[2][3][4] = { {1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 1, 2},
{2, 1, 4, 7, 6, 7, 8, 9, 0, 0, 0, 0} };
printf("%u, %u, %u, %d\n", a, *a, **a, ***a);
return 0;
}
Answer: C
Correct answer: 1002, 1002, 1002, 1
The first three arguments all denote the same address, differing only in type. a is a pointer to the first two-dimensional sub-array, *a a pointer to its first row, and **a a pointer to its first element - but the first element sits at the start of the first row, which sits at the start of the array, so all three are 1002.
Only ***a dereferences all the way through to a value, giving the first element, 1. This is the standard demonstration that an array's address and its first element's address coincide numerically while differing in type.
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