Discussion
What is the output of this C code?
void main()
{
int x = 0;
int *ptr = &5;
printf("%p\n", ptr);
}
Answer: D
Correct answer: Compile time error
The address-of operator requires an lvalue - something with a memory location - and the literal 5 has none. It is a value, not an object, so &5 is rejected outright. The same rule is why you cannot take the address of an arithmetic expression or of the result of a function call returning a value.
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