Discussion
What is the output of this C code?
void foo(int*);
int main()
{
int i = 10, *p = &i;
foo(p++);
}
void foo(int *p)
{
printf("%d\n", *p);
}
Answer: A
Correct answer: 10
The postfix ++ yields the value the pointer had before the increment, so foo receives the original address of i and prints 10. The increment happens to p in main, which afterwards points one int past i - harmless here since it is never dereferenced. Prefix ++p would have passed the advanced pointer and the behaviour would then have been undefined.
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