Discussion
What is the output of this C code?
void main()
{
int k = 5;
int *p = &k;
int **m = &p;
**m = 6;
printf("%d\n", k);
}
Answer: C
Correct answer: 6
**m reaches all the way through to k: m points at p, and p points at k. So the assignment writes 6 into k itself, and printing k confirms it. This is how a double pointer lets code several levels away modify the original object.
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