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Which of the following changes can correct the program so that it prints “Geeks Quiz”?

#include <stdio.h> 
  
void myStrcat(char *a, char *b) 
{ 
    int m = strlen(a); 
    int n = strlen(b); 
    int i; 
    for (i = 0; i <= n; i++) 
       a[m+i]  = b[i]; 
} 
  
int main() 
{ 
    char *str1 = "Geeks "; 
    char *str2 = "Quiz"; 
    myStrcat(str1, str2); 
    printf("%s ", str1); 
    return 0; 
}

A.char *str1 = “Geeks “; can be changed to char str1[100] = “Geeks “;
B.char *str1 = “Geeks “; can be changed to char str1[100] = “Geeks “; and a line a[m+n-1] = ‘\0’ is added at the end of myStrcat
C.A line a[m+n-1] = ‘\0’ is added at the end of myStrcat
D.A line ‘a = (char *)malloc(sizeof(char)*(strlen(a) + strlen(b) + 1)) is added at the beginning of myStrcat()

Answer: A

Correct answer: char *str1 = “Geeks “; can be changed to char str1[100] = “Geeks “;

The fault is that str1 points at a string literal, which must not be modified, and there is no room after it in any case. Making it an array of 100 characters gives writable storage with space to spare. No terminator line is needed, because the copy loop runs to i <= n and so copies b’s own null byte along with its characters.

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