Discussion
Why are Darlington pairs common in output stages?
Answer: D
An output device passing amperes needs tens or hundreds of milliamps of base drive, and a Darlington's multiplied current gain reduces that to a manageable figure. Its saturation voltage is worse rather than better, it dissipates the same or a little more, and its bandwidth is narrower. Cascading to multiply a gain is the obvious move once one device's gain is insufficient, and the penalties land elsewhere as they usually do. The shared properties explain why these belong to one family, and the differences explain why more than one exists.
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