Discussion
An output capacitor works into \( 8 \ \Omega \). For a \( 20 \ \mathrm{Hz} \) break it must be at least about
Answer: A
The break frequency relation with a very small resistance:
\[ C = \frac{1}{2\pi (20)(8)} \approx 1000 \ \mathrm{\mu F} \]
giving about 1000 microfarads, a physically large and expensive part that also distorts a little as its dielectric is worked. That cost, and the distortion, are exactly why split supplies and direct coupling took over.
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