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Halving the supply voltage while holding the frequency changes the dynamic power to

  • A.half of its former value
  • B.an eighth of its former value
  • C.the same value
  • D.a quarter of its former value

Answer: D

Correct answer: a quarter of its former value

Dynamic power is \[ P = \alpha CV^{2}f, \] so at constant frequency it goes as the square of the supply and halving \( V \) leaves a quarter. That quadratic dependence is why voltage scaling is the most powerful lever in low power design, and why a core is run at the lowest voltage its target frequency permits.

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