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A design sleeps for 1 s and wakes for 5 ms. Entering a mode that saves 5 \( \mu \)A but costs 20 ms of re-initialisation is

  • A.a gain provided the core runs at its lowest frequency
  • B.a loss, the wake-up costing more than the sleep saves
  • C.a gain, five microamperes being a large saving
  • D.neutral, the two effects cancelling exactly

Answer: B

The saving over a second is five microampere seconds; the extra twenty milliseconds at, say, five milliamperes costs a hundred. The deep mode pays only when the sleep is long enough to amortise the wake-up, which for these figures means tens of seconds.

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