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An unused input pin left floating on a CMOS device can

  • A.raise the leakage of every other pin on the port
  • B.prevent the device from entering any sleep mode
  • C.draw current by sitting near the switching threshold
  • D.damage the device by exceeding its absolute maximum rating

Answer: C

Correct answer: draw current by sitting near the switching threshold

A floating CMOS input drifts to whatever the leakage and coupling put it at, and if that is near the threshold both transistors of the input stage conduct, drawing a static current that can be hundreds of microamps - ruinous in a battery design and invisible on a schematic. The remedy is to configure every unused pin as an output, or as an input with the internal pull-up or pull-down enabled.

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