Discussion
A wake-up costs 50 \( \mu \)J and the design wakes every 2 s. The average power from wake-ups alone is
Answer: C
Correct answer: 25 \( \mu \)W
\[ \frac{50\ \mu\mathrm{J}}{2\ \mathrm{s}} = 25\ \mu\mathrm{W}. \] Energy divided by the interval gives the average power, and the figure is worth setting against the sleep current: at 3 volts, 25 microwatts is about 8 microamps, so a design sleeping at 1 microamp is dominated by its wake-ups rather than by its sleep.
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