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A task consumes 5 mA for 4 ms at 3 V. The energy per execution is

  • A.20 \( \mu \)J
  • B.15 \( \mu \)J
  • C.600 \( \mu \)J
  • D.60 \( \mu \)J

Answer: D

Five milliamperes at three volts is fifteen milliwatts, and for four milliseconds that is sixty microjoules. Comparing two implementations by energy per execution rather than by current is what reveals which is actually cheaper.

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