Discussion
Halving the clock frequency doubles that task's duration. Its energy per execution then becomes
Answer: A
Correct answer: about the same, the power having halved and the time doubled
Dynamic energy per operation is \( CV^{2} \) per transition and does not depend on frequency, so halving the clock halves the power and doubles the time, leaving the energy essentially unchanged. Slowing down therefore saves nothing by itself - and can cost, since leakage is paid for twice as long. What saves energy is lowering the *voltage*, which the reduced frequency may permit.
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