Machine-translated by Google. Questions are authored in English.
Top

Discussion

A 20 MVA, 50 Hz generator delivers 18 MW over a double circuit line to an infinite bus. The generator has kinetic energy of 2.52 MJ/MVA at rated speed. What is the value of inertia constant?

  • A.\(2.8 \times 10^{-4}\ \mathrm{s^2/elec\ degree}\)
  • B.\(5.8 \times 10^{-4}\ \mathrm{s^2/elec\ degree}\)
  • C.\(7.8 \times 10^{-4}\ \mathrm{s^2/elec\ degree}\)
  • D.\(3.8 \times 10^{-4}\ \mathrm{s^2/elec\ degree}\)

Answer: A

The inertia constant \(M\) in seconds squared per electrical degree is related to the stored energy per MVA, \(H\), by


\[ M = \frac{GH}{180 f} \]


Taking the stored energy of 2.52 MJ/MVA as H on a per MVA basis (G = 1):


\[ \begin{aligned} M = \frac{2.52}{180 \times 50} \\ &= 2.8 \times 10^{-4}\ \text{s}^2/\text{elec degree} \end{aligned} \]


This is the key, option A. If the 20 MVA rating were put in as G, the value would be 20 times larger (5.6e-3), which is not offered, so the item is read per unit MVA. The load of 18 MW is not needed.

No comment is present. Be the first to comment.
Loading…

Post your comment

Please log in or register to post a comment.