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The radiation pressure on a perfectly absorbing surface exposed to a power density \( S \) is

  • A.\( 2S/c \)
  • B.\( S/c^2 \)
  • C.\( S/c \)
  • D.\( Sc \)

Answer: C

The momentum arriving per unit area per unit time is the energy flux divided by the speed of light, and absorbing it delivers that momentum. A perfect reflector receives twice as much, since the momentum is reversed rather than merely stopped.

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