Discussion
In case of n attributes the total number of ultimate class frequencies is :
Answer: C
With n attributes there are \(2^{n}\) ultimate class frequencies.
An ultimate class is specified by stating, for every one of the n attributes, whether it is present or absent, as in ABC, ABγ, AβC and so on. Each attribute gives two choices, so the number of ultimate classes is
\[ 2 \times 2 \times \cdots \times 2 = 2^{n} \]
For two attributes there are four: (AB), (Aβ), (αB) and (αβ). The total number of all class frequencies, of every order, is \(3^{n}\). \(n\) and \(2n\) are far too few, and \(4^{n}\) too many.
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