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Two unbiased dice are thrown. The probability that both dice show the same number is :

  • A.\(\frac{1}{3}\)
  • B.\(\frac{11}{36}\)
  • C.\(\frac{1}{6}\)
  • D.\(\frac{1}{36}\)

Answer: C

The probability is \(\frac{1}{6}\).

Two dice give \(6 \times 6 = 36\) equally likely outcomes. Both show the same number in exactly 6 of them: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6). So

\[ P = \frac{6}{36} = \frac{1}{6} \]

Equivalently, whatever the first die shows, the second matches it with probability 1/6. The value 1/36 is the probability of one particular double, such as two sixes. The value 11/36 is the chance that at least one die shows a given number, such as at least one six, and 1/3 corresponds to no natural count here.

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