Discussion
What is probability of drawing two clubs from a well shuffled pack of 52 cards?
Answer: B
There are 13 clubs in the pack. Draw two without replacement:
\[ P = \frac{13}{52} \times \frac{12}{51} = \frac{1}{4} \times \frac{12}{51} \]
\[ = \frac{12}{204} = \frac{1}{17} \]
Equivalently \( \dfrac{{}^{13}C_{2}}{{}^{52}C_{2}} = \dfrac{78}{1326} = \dfrac{1}{17} \). The second denominator is 51, not 52, because the first card is not replaced.
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