Discussion
A box has 6 black, 4 red, 2 white and 3 blue shirts. What is the probability that 2 red shirts and 1 blue shirt get chosen during a random selection of 3 shirts from the box?
Answer: A
Choose 2 of the 4 red shirts and 1 of the 3 blue, out of all ways to choose 3 from 15.
\[ P = \frac{{}^{4}C_{2} \times {}^{3}C_{1}}{{}^{15}C_{3}} = \frac{6 \times 3}{455} \]
\[ = \frac{18}{455} \]
The two selections are made together, so the counts multiply; the remaining colours play no part.
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