Discussion
A pot has 2 white, 6 black, 4 grey and 8 green balls. If one ball is picked randomly from the pot, what is the probability of it being black or green?
Answer: B
The pot holds \( 2 + 6 + 4 + 8 = 20 \) balls.
Black and green are mutually exclusive, so their probabilities add:
\[ P = \frac{6}{20} + \frac{8}{20} = \frac{14}{20} = \frac{7}{10} \]
No ball is both black and green, so no overlap has to be subtracted.
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