Discussion
If a card is chosen from a standard deck of cards, what is the probability of getting a diamond (♦) or a club(♣)?
Answer: A
A deck has 13 diamonds and 13 clubs, and no card belongs to both suits.
\[ P = \frac{13}{52} + \frac{13}{52} = \frac{26}{52} = \frac{1}{2} \]
The two suits are mutually exclusive, so no overlap is subtracted. Diamonds and clubs together make up exactly half the pack.
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