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A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:

  • A.1/22
  • B.3/22
  • C.2/91
  • D.2/77

Answer: C

The bag holds \( 4 + 5 + 6 = 15 \) balls, 5 of them red.

\[ P = \frac{{}^{5}C_{3}}{{}^{15}C_{3}} = \frac{10}{455} = \frac{2}{91} \]

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