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Brother and sister both appear for an interview. The probability of the selection of brother is \(\frac{1}{6}\), while the probability of rejection of sister is \(\frac{3}{4}\). What is the probability that one of them is selected?

  • A.\(\frac{2}{3}\)
  • B.\(\frac{1}{3}\)
  • C.\(\frac{1}{4}\)
  • D.\(\frac{5}{6}\)

Answer: B

The probability is \(\frac{1}{3}\).

The brother is selected with probability \(\frac{1}{6}\) (rejected \(\frac{5}{6}\)); the sister is rejected with probability \(\frac{3}{4}\), so selected with \(\frac{1}{4}\). Exactly one is selected if the brother is in and the sister out, or the sister in and the brother out:

\[ \begin{aligned} \tfrac{1}{6} \times \tfrac{3}{4} + \tfrac{5}{6} \times \tfrac{1}{4} &= \tfrac{3}{24} + \tfrac{5}{24} \\ &= \tfrac{8}{24} = \tfrac{1}{3} \end{aligned} \]

\(\frac{1}{4}\) is only the sister's chance, and \(\frac{5}{6}\) only the brother's chance of rejection.

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