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When six unbiased dice are rolled simultaneously, the probability of getting all distinct numbers (i.e., 1, 2, 3, 4, 5, and 6) is

  • A.\(\frac{1}{324}\)
  • B.\(\frac{5}{324}\)
  • C.\(\frac{7}{324}\)
  • D.\(\frac{11}{324}\)

Answer: B

The probability is \(\frac{5}{324}\).

Six dice have \(6^{6} = 46656\) equally likely outcomes. All six faces appear exactly once in \(6! = 720\) of them, one for each ordering of the numbers 1 to 6 over the dice.

\[ P = \frac{720}{46656} = \frac{5}{324} \approx 0.0154 \]

\(\frac{1}{324}\) undercounts the orderings by a factor of 5, and \(\frac{7}{324}\) and \(\frac{11}{324}\) do not reduce from \(6!/6^{6}\).

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