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One card is drawn randomly from a well-shuffled pack of 52 cards. The probability of the drawn card being a face card is :

  • A.1
  • B.\(\frac{1}{13}\)
  • C.\(\frac{2}{13}\)
  • D.\(\frac{3}{13}\)

Answer: D

The probability of a face card is \(\frac{3}{13}\).

Face cards are the jack, queen and king of each of the four suits, 3 × 4 = 12 cards in all. So:

\[ P = \frac{12}{52} = \frac{3}{13} \]

1/13 is the probability of one particular rank (say, a king), 2/13 would count only two ranks, and 1 would mean every card is a face card. Counting the aces as face cards, a common error, would give 16/52 = 4/13, which is not offered.

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