Discussion

Ten years ago, P was half of Q's age. If the ratio of their present ages is 3:4, what will be the total of their present age?

Answer: C

Let present age of P and Q be \(3x\) and \(4x\) respectively.

\(\left ( 3x-10 \right )=\frac{1}{2}\left ( 4x-10 \right )\)

\(\Rightarrow\) \(6x-20=4x-10\)

\(\Rightarrow\) \(2x=10\)

\(\Rightarrow \) \(x=5\)

Total of their present age is
\(=3x+4x=7x=7×5=35\)

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