Discussion

Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as old the younger one, find their present age

Answer: B

Let the age of younger person is \(x\)

Then elder person age is \((x+6)\)

so 6 years before

\(3(x-6) = (x+16-6)\)

\(\Rightarrow\) \((3x-18) =( x+10)\)

\(\Rightarrow\) \(x=14\)

So other person age is \(x + 16 = 30\)

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