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The sum of two numbers is 55 and the greater exceeds the smaller by 11. The smaller number is:

  • A.18
  • B.27
  • C.22
  • D.33

Answer: C

The smaller is \(\dfrac{\text{sum} - \text{difference}}{2} = \dfrac{55 - 11}{2} = 22\), and the greater is 33. Check: \(22 + 33 = 55\) and \(33 - 22 = 11\). Halving the sum alone gives 27.5, which is the average rather than either number.

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