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The sum of three consecutive integers is 87. The middle integer is:

  • A.29
  • B.28
  • C.30
  • D.31

Answer: A

Write the integers as \(n-1\), \(n\), \(n+1\); their sum is \(3n = 87\), so \(n = 29\) and the three are 28, 29, 30. For any odd count of consecutive integers the middle one is simply the sum divided by the count, which makes this a one-step problem.

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