Discussion
The sum of four consecutive odd numbers is 80. The smallest of them is:
Answer: C
Write them as \(n\), \(n+2\), \(n+4\), \(n+6\). Their sum is \(4n + 12 = 80\), so \(4n = 68\) and \(n = 17\). The four numbers are 17, 19, 21 and 23. With an even count there is no middle term, so the constant must be subtracted before dividing.
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