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The digits of a two-digit number add up to 9, and reversing the digits increases the number by 27. The number is:

  • A.36
  • B.27
  • C.45
  • D.63

Answer: A

Let the tens digit be \(t\) and the units digit \(u\). Reversing changes the value by \(9(u - t) = 27\), so \(u - t = 3\). With \(t + u = 9\) we get \(u = 6\) and \(t = 3\), making the number 36. Check: \(63 - 36 = 27\). Any reversal difference is always a multiple of 9.

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